From Ohm's law, we have
V = IR
I = V/R
given V = 12 V and R1 = 2 ohm, R2 = 8 ohm and R3 = 4 ohm
Therefore,
net resistance R = R1 + (R2 x R3)/ (R2 + R3)
= 2 + (8 x 4/8 + 4)
= 2 + 32/12
= 2 + 2.66 R
= 4.66 ohm
I = 12/4.66
I = 2.58 A
She can use ammeter S to measure the current in the circuit.